What is the derivative of (6x^7/(5tan(x))) ?

The derivative of (6x^7/(5tan(x))) is (6(7x^6tan(x)-x^7sec^2(x)))/(5tan^2(x))

What is the first derivative of (6x^7/(5tan(x))) ?

The first derivative of (6x^7/(5tan(x))) is (6(7x^6tan(x)-x^7sec^2(x)))/(5tan^2(x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{6 x ^{7}}{5 tan ( x )})

\frac{6 ( 7 x ^{6} tan ( x ) - x ^{7} sec ^{2} ( x ) )}{5 tan ^{2} ( x )}

Solution steps

\frac{d}{d x} (\frac{6 x ^{7}}{5 tan ( x )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{6}{5} \frac{d}{d x} (\frac{x ^{7}}{tan ( x )})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{6}{5} \cdot \frac{\frac{d}{d x} ( x ^{7} ) tan ( x ) - \frac{d}{d x} ( tan ( x ) ) x ^{7}}{( tan ( x ) ) ^{2}}

\frac{d}{d x} (x^{7}) = 7 x^{6}

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= \frac{6}{5} \cdot \frac{7 x ^{6} tan ( x ) - sec ^{2} ( x ) x ^{7}}{( tan ( x ) ) ^{2}}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{6 ( 7 x ^{6} tan ( x ) - x ^{7} sec ^{2} ( x ) )}{5 tan ^{2} ( x )}

\frac{d}{d x} (\frac{2 x + 5 x ^{- \frac{2}{5}}}{x ^{2} + 1})

\frac{\partial}{\partial x} (x^{4} y^{3} - 4 x^{2} y + y^{5})

f (x) = cos (\frac{π x}{2}), at x = 0.8

f (x) = 2 x^{4} e^{x}

\int \frac{x ^{3}}{3} - \frac{5 x ^{2}}{2} + 6 x + C d x

What is the derivative of (6x^7/(5tan(x))) ?
The derivative of (6x^7/(5tan(x))) is (6(7x^6tan(x)-x^7sec^2(x)))/(5tan^2(x))
What is the first derivative of (6x^7/(5tan(x))) ?
The first derivative of (6x^7/(5tan(x))) is (6(7x^6tan(x)-x^7sec^2(x)))/(5tan^2(x))