What is the sum from n=1 to infinity of 4/(n^4) ?

The sum from n=1 to infinity of 4/(n^4) is converges

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sum from n=1 to infinity of 4/(n^4)

n = 1 \sum \infty \frac{4}{n ^{4}}

converges

Solution steps

n = 1 \sum \infty \frac{4}{n ^{4}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 4 \cdot n = 1 \sum \infty \frac{1}{n ^{4}}

Apply p-Series Test:

converges

= 4 converges

= converges

y = \frac{6}{x - 1}, (3, 3)

\int \frac{1}{y ^{2} + 9} d y

(14 x - x^{2})^{3}

f (x) = \frac{1}{x}, at x = 9

\frac{4}{e ^{2 x}}

What is the sum from n=1 to infinity of 4/(n^4) ?
The sum from n=1 to infinity of 4/(n^4) is converges