What is the first d/(da)((-9)-(-7a)) ?

The first d/(da)((-9)-(-7a)) is 7

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d/(da)((-9)-(-7a))

\frac{d}{d a} ((- 9) - (- 7 a))

7

Solution steps

\frac{d}{d a} ((- 9) - (- 7 a))

Simplify

(- 9) - (- 7 a) : - 9 + 7 a

= \frac{d}{d a} (- 9 + 7 a)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d a} (9) + \frac{d}{d a} (7 a)

\frac{d}{d a} (9) = 0

\frac{d}{d a} (7 a) = 7

= - 0 + 7

Simplify

= 7

y^{^{'}} + x^{- 1} y = x y^{2}

f (x) = e^{x}, at x = 0

f (x) = 7 x^{3} + 7 x^{2} + 7 x + 3

\frac{d}{d x} ((x^{4} - 1)^{3} (x^{3} + 1)^{4})

\int_{1}^{2} \frac{1}{8 - 3 t} d t