What is the derivative of ln(8-x^2) ?

The derivative of ln(8-x^2) is -(2x)/(8-x^2)

What is the first derivative of ln(8-x^2) ?

The first derivative of ln(8-x^2) is -(2x)/(8-x^2)

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\frac{d}{d x} (ln (8 - x^{2}))

- \frac{2 x}{8 - x ^{2}}

Solution steps

\frac{d}{d x} (ln (8 - x^{2}))

Apply the chain rule:

\frac{1}{8 - x ^{2}} \frac{d}{d x} (8 - x^{2})

= \frac{1}{8 - x ^{2}} \frac{d}{d x} (8 - x^{2})

\frac{d}{d x} (8 - x^{2}) = - 2 x

= \frac{1}{8 - x ^{2}} (- 2 x)

Simplify

\frac{1}{8 - x ^{2}} (- 2 x) : - \frac{2 x}{8 - x ^{2}}

= - \frac{2 x}{8 - x ^{2}}

y = arcsin (5 x + 1)

\frac{\partial}{\partial x} (y^{5} cos (4 x))

\frac{\partial}{\partial x} ((x^{2} + y^{2})^{- \frac{15}{2}} x)

x \to 0 - lim (\frac{3}{x})

\frac{d}{d x} ((ln (x))^{6})

What is the derivative of ln(8-x^2) ?
The derivative of ln(8-x^2) is -(2x)/(8-x^2)
What is the first derivative of ln(8-x^2) ?
The first derivative of ln(8-x^2) is -(2x)/(8-x^2)