What is the solution for derivative of (q^2+45q+875/3)=0 ?

The solution for derivative of (q^2+45q+875/3)=0 is q(x)=c_{1},q(x)=c_{1}

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derivative of (q^2+45q+875/3)=0

\frac{d}{d x} (\frac{q ^{2} + 45 q + 875}{3}) = 0

q (x) = c_{1}, q (x) = c_{1}

Solution steps

\frac{d}{d x} (\frac{q ( x ) ^{2} + 45 q ( x ) + 875}{3}) = 0

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

\frac{q ( x ) ^{2} + 45 q ( x ) + 875}{3} = \int 0 d x

\int 0 d x = c_{1}

\frac{q ( x ) ^{2} + 45 q ( x ) + 875}{3} = c_{1}

Isolate

q (x) : q (x) = \frac{- 45 + 12 c _{1} - 1475}{2}, q (x) = \frac{- 45 - 12 c _{1} - 1475}{2}

q (x) = \frac{- 45 + 12 c _{1} - 1475}{2}, q (x) = \frac{- 45 - 12 c _{1} - 1475}{2}

Simplify

q (x) = c_{1}, q (x) = c_{1}

f (x) = 8 x - 3 x^{2}, (- 3, - 51)

e^{3}

f (x) = - 3 x

\frac{d}{d x} (4 - x^{2} - y^{2})

lo g_{10} (x + 5)

What is the solution for derivative of (q^2+45q+875/3)=0 ?
The solution for derivative of (q^2+45q+875/3)=0 is q(x)=c_{1},q(x)=c_{1}