What is the derivative of xe^{(-2x^2}) ?

The derivative of xe^{(-2x^2}) is e^{-2x^2}-4e^{-2x^2}x^2

What is the first derivative of xe^{(-2x^2}) ?

The first derivative of xe^{(-2x^2}) is e^{-2x^2}-4e^{-2x^2}x^2

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\frac{d}{d x} (x e^{(- 2 x^{2})})

e^{- 2 x^{2}} - 4 e^{- 2 x^{2}} x^{2}

Solution steps

\frac{d}{d x} (x e^{(- 2 x^{2})})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{- 2 x^{2}}

= \frac{d x}{d x} e^{- 2 x^{2}} + \frac{d}{d x} (e^{- 2 x^{2}}) x

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{- 2 x^{2}}) = - 4 e^{- 2 x^{2}} x

= 1 \cdot e^{- 2 x^{2}} + (- 4 e^{- 2 x^{2}} x) x

Simplify

1 \cdot e^{- 2 x^{2}} + (- 4 e^{- 2 x^{2}} x) x : e^{- 2 x^{2}} - 4 e^{- 2 x^{2}} x^{2}

= e^{- 2 x^{2}} - 4 e^{- 2 x^{2}} x^{2}

∣ x ∣, \frac{x}{2} + 3

x^{3} - 4 x^{2} - 9 x + 9

\int \frac{1}{4 + ( x - 1 ) ^{2}} d x

\frac{d}{d x} (x^{3} \cdot sin (x))

\int 9 x^{- 1} d x

What is the derivative of xe^{(-2x^2}) ?
The derivative of xe^{(-2x^2}) is e^{-2x^2}-4e^{-2x^2}x^2
What is the first derivative of xe^{(-2x^2}) ?
The first derivative of xe^{(-2x^2}) is e^{-2x^2}-4e^{-2x^2}x^2