What is the tangent of f(t)=3t-t^2,(0,0) ?

The tangent of f(t)=3t-t^2,(0,0) is y=3t

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tangent of f(t)=3t-t^2,(0,0)

tangent of

f (t) = 3 t - t^{2}, (0, 0)

y = 3 t

Solution steps

Find the slope of

f (t) = 3 t - t^{2} : \frac{df ( t )}{d t} = 3 - 2 t

Compute the slope of

f (t) = 3 t - t^{2}

(0, 0) : m = 3

Find the line with slope m=

3

and passing through

(0, 0) : y = 3 t

y = 3 t

\int (x + 3)^{4} d x

\frac{d}{d x} (x^{2} sin (y))

y^{^{'}} = 100 - y

\frac{d}{d x} ((2 x + 1)^{5} (x^{4} - 3)^{6})

\int (\frac{60}{2 x + 5} - 4) d x

What is the tangent of f(t)=3t-t^2,(0,0) ?
The tangent of f(t)=3t-t^2,(0,0) is y=3t