What is the derivative of 1/x-x ?

The derivative of 1/x-x is -1/(x^2)-1

What is the first derivative of 1/x-x ?

The first derivative of 1/x-x is -1/(x^2)-1

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\frac{d}{d x} (\frac{1}{x} - x)

- \frac{1}{x ^{2}} - 1

Solution steps

\frac{d}{d x} (\frac{1}{x} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{x}) - \frac{d x}{d x}

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

\frac{d x}{d x} = 1

= - \frac{1}{x ^{2}} - 1

\int x + 2 d x

f (t) = 3 t sin (π t)

\int 3 x \cdot 2^{x^{2}} d x

x \to 0 lim (\frac{sin ( x )}{3 x})

x^{3} + y^{3} = 7 x y, (2, - 4)

What is the derivative of 1/x-x ?
The derivative of 1/x-x is -1/(x^2)-1
What is the first derivative of 1/x-x ?
The first derivative of 1/x-x is -1/(x^2)-1