What is the derivative of (ln(2x)/(5x)) ?

The derivative of (ln(2x)/(5x)) is (1-ln(2x))/(5x^2)

What is the first derivative of (ln(2x)/(5x)) ?

The first derivative of (ln(2x)/(5x)) is (1-ln(2x))/(5x^2)

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\frac{d}{d x} (\frac{ln ( 2 x )}{5 x})

\frac{1 - ln ( 2 x )}{5 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{ln ( 2 x )}{5 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{5} \frac{d}{d x} (\frac{ln ( 2 x )}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{5} \cdot \frac{\frac{d}{d x} ( ln ( 2 x ) ) x - \frac{d x}{d x} ln ( 2 x )}{x ^{2}}

\frac{d}{d x} (ln (2 x)) = \frac{1}{x}

\frac{d x}{d x} = 1

= \frac{1}{5} \cdot \frac{\frac{1}{x} x - 1 \cdot ln ( 2 x )}{x ^{2}}

Simplify

\frac{1}{5} \cdot \frac{\frac{1}{x} x - 1 \cdot ln ( 2 x )}{x ^{2}} : \frac{1 - ln ( 2 x )}{5 x ^{2}}

= \frac{1 - ln ( 2 x )}{5 x ^{2}}

\int cos^{2} (\frac{1}{2} x) d x

\int \frac{x ^{2} - 5 x + 6}{x ^{2} + 4} d x

\frac{\partial}{\partial x} ((\frac{y}{x})^{\frac{3}{4}})

\frac{\partial}{\partial y} (e^{x} cos (2 y))

y^{^{'}} + 4 y = 32 x, y (0) = 3

What is the derivative of (ln(2x)/(5x)) ?
The derivative of (ln(2x)/(5x)) is (1-ln(2x))/(5x^2)
What is the first derivative of (ln(2x)/(5x)) ?
The first derivative of (ln(2x)/(5x)) is (1-ln(2x))/(5x^2)