What is (\partial)/(\partial x)(7xy+xcos(x)) ?

The answer to (\partial)/(\partial x)(7xy+xcos(x)) is 7y+cos(x)-xsin(x)

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(\partial)/(\partial x)(7xy+xcos(x))

\frac{\partial}{\partial x} (7 x y + x cos (x))

7 y + cos (x) - x sin (x)

Solution steps

\frac{\partial}{\partial x} (7 x y + x cos (x))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (7 x y) + \frac{\partial}{\partial x} (x cos (x))

\frac{\partial}{\partial x} (7 x y) = 7 y

\frac{\partial}{\partial x} (x cos (x)) = cos (x) - x sin (x)

= 7 y + cos (x) - x sin (x)

- x^{2} + 4, 3 x

\int (8 x + 5)^{- 3} d x

\frac{d}{d x} ((8 x^{2} - 13 x) e^{x})

\int_{0}^{- 1} (- 16 3 x) d x

x \to - 1 lim (\frac{x ^{2} - 7}{1 - x})

What is (\partial)/(\partial x)(7xy+xcos(x)) ?
The answer to (\partial)/(\partial x)(7xy+xcos(x)) is 7y+cos(x)-xsin(x)