What is the derivative of sin(x^2+pi) ?

The derivative of sin(x^2+pi) is -cos(x^2)*2x

What is the first derivative of sin(x^2+pi) ?

The first derivative of sin(x^2+pi) is -cos(x^2)*2x

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\frac{d}{d x} (sin (x^{2} + π))

- cos (x^{2}) \cdot 2 x

Solution steps

\frac{d}{d x} (sin (x^{2} + π))

Simplify

sin (x^{2} + π) : - sin (x^{2})

= \frac{d}{d x} (- sin (x^{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (sin (x^{2}))

Apply the chain rule:

cos (x^{2}) \frac{d}{d x} (x^{2})

= cos (x^{2}) \frac{d}{d x} (x^{2})

\frac{d}{d x} (x^{2}) = 2 x

= - cos (x^{2}) \cdot 2 x

y = x^{x} \frac{d y}{d x}

\frac{d}{d x} (\frac{e ^{x} + e ^{- x}}{2})

\int e^{y} \cdot y^{2} d y

\int \frac{- 1}{x ^{2} + 1} d x

x (x - 14)

What is the derivative of sin(x^2+pi) ?
The derivative of sin(x^2+pi) is -cos(x^2)*2x
What is the first derivative of sin(x^2+pi) ?
The first derivative of sin(x^2+pi) is -cos(x^2)*2x