What is the derivative of 3/(4x+1) ?

The derivative of 3/(4x+1) is -(12)/((4x+1)^2)

What is the first derivative of 3/(4x+1) ?

The first derivative of 3/(4x+1) is -(12)/((4x+1)^2)

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derivative of

\frac{3}{4 x + 1}

- \frac{12}{( 4 x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3}{4 x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{4 x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} ((4 x + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( 4 x + 1 ) ^{2}} \frac{d}{d x} (4 x + 1)

= - \frac{1}{( 4 x + 1 ) ^{2}} \frac{d}{d x} (4 x + 1)

\frac{d}{d x} (4 x + 1) = 4

= 3 (- \frac{1}{( 4 x + 1 ) ^{2}} \cdot 4)

Simplify

3 (- \frac{1}{( 4 x + 1 ) ^{2}} \cdot 4) : - \frac{12}{( 4 x + 1 ) ^{2}}

= - \frac{12}{( 4 x + 1 ) ^{2}}

\frac{d}{d x} (\frac{2 x}{x ^{2} + 1})

\frac{d}{d x} ((x - 4)^{3} e^{- 4 x})

\frac{d y}{d x} = e^{3 x + 5 y}

\int 4 tan^{3} (x) sec^{2} (x) d x

\frac{d}{d x} ((x^{2} + 1) arctan (x))

What is the derivative of 3/(4x+1) ?
The derivative of 3/(4x+1) is -(12)/((4x+1)^2)
What is the first derivative of 3/(4x+1) ?
The first derivative of 3/(4x+1) is -(12)/((4x+1)^2)