What is the derivative of f(x)=sqrt(2-2x) ?

The derivative of f(x)=sqrt(2-2x) is -1/(sqrt(2-2x))

What is the first derivative of f(x)=sqrt(2-2x) ?

The first derivative of f(x)=sqrt(2-2x) is -1/(sqrt(2-2x))

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derivative of

f (x) = 2 - 2 x

- \frac{1}{2 - 2 x}

Solution steps

\frac{d}{d x} (2 - 2 x)

Apply the chain rule:

\frac{1}{2 2 - 2 x} \frac{d}{d x} (2 - 2 x)

= \frac{1}{2 2 - 2 x} \frac{d}{d x} (2 - 2 x)

\frac{d}{d x} (2 - 2 x) = - 2

= \frac{1}{2 2 - 2 x} (- 2)

Simplify

\frac{1}{2 2 - 2 x} (- 2) : - \frac{1}{2 - 2 x}

= - \frac{1}{2 - 2 x}

f^{^{''}} (x) = x^{2}, f^{^{'}} (0) = 6, f (0) = 3

x \to \infty lim (\frac{8 - e ^{x}}{8 + 3 e ^{x}})

\int \frac{ln ( 3 x )}{2 x} d x

e^{x} + e^{- 3 x}

\int 9 sin^{2} (x) d x

What is the derivative of f(x)=sqrt(2-2x) ?
The derivative of f(x)=sqrt(2-2x) is -1/(sqrt(2-2x))
What is the first derivative of f(x)=sqrt(2-2x) ?
The first derivative of f(x)=sqrt(2-2x) is -1/(sqrt(2-2x))