What is the derivative of ln(sqrt(2x+1)) ?

The derivative of ln(sqrt(2x+1)) is 1/(2x+1)

What is the first derivative of ln(sqrt(2x+1)) ?

The first derivative of ln(sqrt(2x+1)) is 1/(2x+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

ln (2 x + 1)

\frac{1}{2 x + 1}

Solution steps

\frac{d}{d x} (ln (2 x + 1))

Apply the chain rule:

\frac{1}{2 x + 1} \frac{d}{d x} (2 x + 1)

= \frac{1}{2 x + 1} \frac{d}{d x} (2 x + 1)

\frac{d}{d x} (2 x + 1) = \frac{1}{2 x + 1}

= \frac{1}{2 x + 1} \cdot \frac{1}{2 x + 1}

Simplify

\frac{1}{2 x + 1} \cdot \frac{1}{2 x + 1} : \frac{1}{2 x + 1}

= \frac{1}{2 x + 1}

\int_{0}^{\frac{3}{4}} 30 x d x

f (x) = x + 9 x

x \to - \infty lim (cos (x))

\frac{d}{d x} (ln (x + 1) + \frac{x}{x + 1})

x \to 2 lim (x^{2} + 1)

What is the derivative of ln(sqrt(2x+1)) ?
The derivative of ln(sqrt(2x+1)) is 1/(2x+1)
What is the first derivative of ln(sqrt(2x+1)) ?
The first derivative of ln(sqrt(2x+1)) is 1/(2x+1)