What is the derivative of f(x)=x-1/x ?

The derivative of f(x)=x-1/x is 1+1/(x^2)

What is the first derivative of f(x)=x-1/x ?

The first derivative of f(x)=x-1/x is 1+1/(x^2)

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derivative of

f (x) = x - \frac{1}{x}

1 + \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (x - \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (\frac{1}{x})

\frac{d x}{d x} = 1

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= 1 - (- \frac{1}{x ^{2}})

Simplify

= 1 + \frac{1}{x ^{2}}

\int_{0}^{1} x^{5} ln (x) d x

\frac{d}{d x} (3 arctan (2 x))

\int (\frac{z ^{4} + 10 z ^{3}}{2 z ^{2}}) d z

y^{^{'}} - \frac{2 y}{x} = x^{2} e^{x}

\frac{\partial}{\partial x} (e^{- k x^{2}})

What is the derivative of f(x)=x-1/x ?
The derivative of f(x)=x-1/x is 1+1/(x^2)
What is the first derivative of f(x)=x-1/x ?
The first derivative of f(x)=x-1/x is 1+1/(x^2)