What is (\partial)/(\partial x)(xy+yz-xz) ?

The answer to (\partial)/(\partial x)(xy+yz-xz) is y-z

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(\partial)/(\partial x)(xy+yz-xz)

\frac{\partial}{\partial x} (x y + yz - x z)

y - z

Solution steps

\frac{\partial}{\partial x} (x y + yz - x z)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x y) + \frac{\partial}{\partial x} (yz) - \frac{\partial}{\partial x} (x z)

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (yz) = 0

\frac{\partial}{\partial x} (x z) = z

= y + 0 - z

Simplify

= y - z

\frac{1}{( s ^{2} + 1 ) ( s ^{2} + 2 s + 3 )}

\int \frac{cos ( x )}{cos ^{3} ( x )} d x

(cos (x))^{x}

x \to 2 lim (lo g_{10} (x - 2))

x \to 0 lim ((1 - 2 x)^{\frac{1}{x ^{2}}})

What is (\partial)/(\partial x)(xy+yz-xz) ?
The answer to (\partial)/(\partial x)(xy+yz-xz) is y-z