What is laplacetransform 2sin(5t) ?

The answer to laplacetransform 2sin(5t) is (10)/(s^2+25)

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laplacetransform 2sin(5t)

laplace transform

2 sin (5 t)

\frac{10}{s ^{2} + 25}

Solution steps

L {2 sin (5 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 2 L {sin (5 t)}

L {sin (5 t)} : \frac{5}{s ^{2} + 25}

= 2 \cdot \frac{5}{s ^{2} + 25}

Refine

2 \frac{5}{s ^{2} + 25} : \frac{10}{s ^{2} + 25}

= \frac{10}{s ^{2} + 25}

\int x cos (k x) d x

y^{^{''}} + 0.1 y^{^{'}} + 0.0004 y = 1

n = 1 \sum \infty (\frac{2}{3})^{2 n}

\int_{0}^{l n (13)} x e^{x} d x

\int \frac{1}{6 r - 7} d r

What is laplacetransform 2sin(5t) ?
The answer to laplacetransform 2sin(5t) is (10)/(s^2+25)