What is the integral of (sqrt(x))/(x^4) ?

The integral of (sqrt(x))/(x^4) is -2/(5x^{5/2)}+C

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integral of (sqrt(x))/(x^4)

\int \frac{x}{x ^{4}} d x

- \frac{2}{5 x ^{\frac{5}{2}}} + C

Solution steps

\int \frac{x}{x ^{4}} d x

Simplify

\frac{x}{x ^{4}} : \frac{1}{x ^{\frac{7}{2}}}

= \int \frac{1}{x ^{\frac{7}{2}}} d x

Apply the Power Rule

: - \frac{2}{5 x ^{\frac{5}{2}}}

= - \frac{2}{5 x ^{\frac{5}{2}}}

Add a constant to the solution

= - \frac{2}{5 x ^{\frac{5}{2}}} + C

\frac{d}{d x} (\frac{e ^{x} - 1}{x})

\int 2 x^{3} e^{3 x^{4}} d x

\int_{1}^{2} x^{2} + 2 x d x

\int_{0}^{π} sin (5 x) d x

y = (x^{3} - 16 x)^{12}

What is the integral of (sqrt(x))/(x^4) ?
The integral of (sqrt(x))/(x^4) is -2/(5x^{5/2)}+C