What is the derivative of 3/(2x-1) ?

The derivative of 3/(2x-1) is -6/((2x-1)^2)

What is the first derivative of 3/(2x-1) ?

The first derivative of 3/(2x-1) is -6/((2x-1)^2)

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\frac{d}{d x} (\frac{3}{2 x - 1})

- \frac{6}{( 2 x - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3}{2 x - 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{2 x - 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} ((2 x - 1)^{- 1})

Apply the chain rule:

- \frac{1}{( 2 x - 1 ) ^{2}} \frac{d}{d x} (2 x - 1)

= - \frac{1}{( 2 x - 1 ) ^{2}} \frac{d}{d x} (2 x - 1)

\frac{d}{d x} (2 x - 1) = 2

= 3 (- \frac{1}{( 2 x - 1 ) ^{2}} \cdot 2)

Simplify

3 (- \frac{1}{( 2 x - 1 ) ^{2}} \cdot 2) : - \frac{6}{( 2 x - 1 ) ^{2}}

= - \frac{6}{( 2 x - 1 ) ^{2}}

\frac{d}{d x} ((4 x^{2} - 13)^{- 11})

\int \frac{( x ^{2} )}{9 + x ^{6}} d x

\frac{d}{d x} (x^{- 11})

\int \frac{10}{( 5 - 4 x - x ^{2} ) ^{\frac{5}{2}}} d x

y^{^{''}} + y = 2

What is the derivative of 3/(2x-1) ?
The derivative of 3/(2x-1) is -6/((2x-1)^2)
What is the first derivative of 3/(2x-1) ?
The first derivative of 3/(2x-1) is -6/((2x-1)^2)