What is the tangent of f(x)=8x^4,\at x=2 ?

The tangent of f(x)=8x^4,\at x=2 is y=256x-384

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tangent of f(x)=8x^4,\at x=2

tangent of

f (x) = 8 x^{4}, at x = 2

y = 256 x - 384

Solution steps

Find the tangent point:

(2, 128)

Find the slope of

f (x) = 8 x^{4} : \frac{df ( x )}{d x} = 32 x^{3}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 256

Find the line with slope m=

256

and passing through

(2, 128) : y = 256 x - 384

y = 256 x - 384

y = x^{3} (2 x - 5)^{4}

\frac{d}{d x} (2 x^{2} - 7)

- e^{x} y \frac{d y}{d x} = e^{- y} + e^{- 2 x - y}

\frac{d}{d x} (\frac{x}{e ^{x^{2}}})

\int \frac{x ^{2}}{( 1 + x ^{2} ) ^{2}} d x

What is the tangent of f(x)=8x^4,\at x=2 ?
The tangent of f(x)=8x^4,\at x=2 is y=256x-384