What is the solution for xy^'=y+7x^2sin(x),y(pi)=0 ?

The solution for xy^'=y+7x^2sin(x),y(pi)=0 is y=-7xcos(x)-7x

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xy^'=y+7x^2sin(x),y(pi)=0

x y^{^{'}} = y + 7 x^{2} sin (x), y (π) = 0

y = - 7 x cos (x) - 7 x

Solution steps

x y^{'} (x) = y + 7 x^{2} sin (x)

Solve linear ODE:

y = - 7 x cos (x) - 7 x

y = - 7 x cos (x) - 7 x

x \to 1 lim (5 x + 6)

\frac{d}{d x} (- 3^{- 2} (tan (7 x))^{5})

(2 cos (x))^{^{'}}

y^{2} = x - 2, y = x - 4

\int (sec (2 x) + tan (2 x)) d x

What is the solution for xy^'=y+7x^2sin(x),y(pi)=0 ?
The solution for xy^'=y+7x^2sin(x),y(pi)=0 is y=-7xcos(x)-7x