What is the solution for (dy}{dx}=\frac{x+y+1)/x ?

The solution for (dy}{dx}=\frac{x+y+1)/x is y=xln(x)-1+c_{1}x

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(dy}{dx}=\frac{x+y+1)/x

\frac{d y}{d x} = \frac{x + y + 1}{x}

y = x ln (x) - 1 + c_{1} x

Solution steps

\frac{d y}{d x} = \frac{x + y + 1}{x}

Solve linear ODE:

y = x ln (x) - 1 + c_{1} x

y = x ln (x) - 1 + c_{1} x

\frac{d}{d x} (arctan (\frac{( x - 1 )}{( x + 1 )}))

x \to 1 - lim (g (x))

\frac{d}{d x} (- \frac{5}{x ^{3}} \cdot e^{- 3 x^{4} + 4 x^{2}})

f (x) = \frac{( x ^{2} - 1 )}{4 x + 1}, at x = 1

\frac{6}{ln ( x )}

What is the solution for (dy}{dx}=\frac{x+y+1)/x ?
The solution for (dy}{dx}=\frac{x+y+1)/x is y=xln(x)-1+c_{1}x