What is the integral of (sin^3(x))/(1-cos^2(x)) ?

The integral of (sin^3(x))/(1-cos^2(x)) is -cos(x)+C

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integral of (sin^3(x))/(1-cos^2(x))

\int \frac{sin ^{3} ( x )}{1 - cos ^{2} ( x )} d x

- cos (x) + C

Solution steps

\int \frac{sin ^{3} ( x )}{1 - cos ^{2} ( x )} d x

Rewrite using trig identities

= \int sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= - cos (x)

Add a constant to the solution

= - cos (x) + C

\int u^{\frac{1}{3}} d u

\frac{\partial}{\partial x} (sin (x) - cos (x y))

\frac{\partial}{\partial x} (63 x^{3} cos (9 x^{2} y))

f (x) = - 8 cos (2 x)

\int_{- 3}^{3} (9 - x^{2}) d x

What is the integral of (sin^3(x))/(1-cos^2(x)) ?
The integral of (sin^3(x))/(1-cos^2(x)) is -cos(x)+C