What is the sum from n=1 to infinity of n^{3/2} ?

The sum from n=1 to infinity of n^{3/2} is diverges

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sum from n=1 to infinity of n^{3/2}

n = 1 \sum \infty n^{\frac{3}{2}}

diverges

Solution steps

n = 1 \sum \infty n^{\frac{3}{2}}

Apply Series Divergence Test:

diverges

= diverges

t \cdot \frac{d y}{d t} = t^{3} + 11 t^{3} y

2 x^{5} + 3 x^{3} - 3

x \to \infty lim (- 3^{- x})

f (x) = x (x^{- 1} + 7)

\int (y - 4) d y

What is the sum from n=1 to infinity of n^{3/2} ?
The sum from n=1 to infinity of n^{3/2} is diverges