What is the derivative of (x+1/3) ?

The derivative of (x+1/3) is 1/3

What is the first derivative of (x+1/3) ?

The first derivative of (x+1/3) is 1/3

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\frac{d}{d x} (\frac{x + 1}{3})

\frac{1}{3}

Solution steps

\frac{d}{d x} (\frac{x + 1}{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} \frac{d}{d x} (x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{3} (\frac{d x}{d x} + \frac{d}{d x} (1))

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= \frac{1}{3} (1 + 0)

Simplify

= \frac{1}{3}

\int_{1}^{5} \frac{x ^{2} + 3}{6 x - x ^{2}} d x

\int t + 1 d t

\frac{d}{d x} ((3 x) (x + 3))

y^{^{''}} + 25 y = 2 sec (5 t)

x \to 0 lim (5^{x})

What is the derivative of (x+1/3) ?
The derivative of (x+1/3) is 1/3
What is the first derivative of (x+1/3) ?
The first derivative of (x+1/3) is 1/3