What is the tangent of f(x)=5sqrt(x),\at x=1 ?

The tangent of f(x)=5sqrt(x),\at x=1 is y= 5/2 x+5/2

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tangent of f(x)=5sqrt(x),\at x=1

tangent of

f (x) = 5 x, at x = 1

y = \frac{5}{2} x + \frac{5}{2}

Solution steps

Find the tangent point:

(1, 5)

Find the slope of

f (x) = 5 x : \frac{df ( x )}{d x} = \frac{5}{2 x}

Compute the slope of

f (x) = 5 x

x = 1 : m = \frac{5}{2}

Find the line with slope m=

\frac{5}{2}

and passing through

(1, 5) : y = \frac{5}{2} x + \frac{5}{2}

y = \frac{5}{2} x + \frac{5}{2}

t^{3} \cdot cos (3 t)

x \to 0 lim (x + 1)

\frac{\partial}{\partial z} (\frac{y}{x ^{2} + y ^{2} + z ^{2}})

\frac{d ^{6}}{d x ^{6}} (x^{- 7})

\int (3 x + cos (x)) d x

What is the tangent of f(x)=5sqrt(x),\at x=1 ?
The tangent of f(x)=5sqrt(x),\at x=1 is y= 5/2 x+5/2