What is the derivative of 5/(sqrt(x^2+16)) ?

The derivative of 5/(sqrt(x^2+16)) is -(5x)/((x^2+16)^{3/2)}

What is the first derivative of 5/(sqrt(x^2+16)) ?

The first derivative of 5/(sqrt(x^2+16)) is -(5x)/((x^2+16)^{3/2)}

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\frac{d}{d x} (\frac{5}{x ^{2} + 16})

- \frac{5 x}{( x ^{2} + 16 ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{5}{x ^{2} + 16})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (\frac{1}{x ^{2} + 16})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 5 \frac{d}{d x} ((x^{2} + 16)^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( x ^{2} + 16 ) ^{\frac{3}{2}}} \frac{d}{d x} (x^{2} + 16)

= - \frac{1}{2 ( x ^{2} + 16 ) ^{\frac{3}{2}}} \frac{d}{d x} (x^{2} + 16)

\frac{d}{d x} (x^{2} + 16) = 2 x

= 5 (- \frac{1}{2 ( x ^{2} + 16 ) ^{\frac{3}{2}}} \cdot 2 x)

Simplify

5 (- \frac{1}{2 ( x ^{2} + 16 ) ^{\frac{3}{2}}} \cdot 2 x) : - \frac{5 x}{( x ^{2} + 16 ) ^{\frac{3}{2}}}

= - \frac{5 x}{( x ^{2} + 16 ) ^{\frac{3}{2}}}

\frac{d}{d x} (\frac{2}{1 - x})

x \to - 5 - lim (\frac{- 4 x}{x + 5})

\int \frac{ln ( t ) t ^{- 1}}{- 3} d t

\frac{d}{d x} (ln (x^{2} + y^{3}))

\int x^{3} 4 - x^{2} d x

What is the derivative of 5/(sqrt(x^2+16)) ?
The derivative of 5/(sqrt(x^2+16)) is -(5x)/((x^2+16)^{3/2)}
What is the first derivative of 5/(sqrt(x^2+16)) ?
The first derivative of 5/(sqrt(x^2+16)) is -(5x)/((x^2+16)^{3/2)}