What is the integral of e^{-0.3x} ?

The integral of e^{-0.3x} is -3.33333…e^{-0.3x}+C

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integral of e^{-0.3x}

\int e^{- 0.3 x} d x

- 3.33333 \dots e^{- 0.3 x} + C

Solution steps

\int e^{- 0.3 x} d x

Apply u-substitution

: \int - \frac{1}{0.3} e^{u} d u

= \int - \frac{1}{0.3} e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{0.3} \cdot \int e^{u} d u

Simplify

= - 3.33333 \dots \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= - 3.33333 \dots e^{u}

Substitute back

u = - 0.3 x

= - 3.33333 \dots e^{- 0.3 x}

Add a constant to the solution

= - 3.33333 \dots e^{- 0.3 x} + C

cos (x^{2}) sin (x)

\frac{x - 5}{9 x ^{2} e ^{x}}

\frac{\partial}{\partial x} (2 x + y)

y^{^{'''}} + 3 y^{^{''}} + y^{^{'}} - 5 y = 0

\int 7 x^{6} d x

What is the integral of e^{-0.3x} ?
The integral of e^{-0.3x} is -3.33333…e^{-0.3x}+C