What is the derivative of y=sqrt(3x) ?

The derivative of y=sqrt(3x) is (sqrt(3))/(2sqrt(x))

What is the first derivative of y=sqrt(3x) ?

The first derivative of y=sqrt(3x) is (sqrt(3))/(2sqrt(x))

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derivative of

y = 3 x

\frac{3}{2 x}

Solution steps

\frac{d}{d x} (3 x)

Apply the chain rule:

\frac{1}{2 3 x} \frac{d}{d x} (3 x)

= \frac{1}{2 3 x} \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= \frac{1}{2 3 x} \cdot 3

Simplify

\frac{1}{2 3 x} \cdot 3 : \frac{3}{2 x}

= \frac{3}{2 x}

x \to 3 lim (2 x^{3} + 4 x - 2)

\frac{d}{d x} (2 a x)

\int (x + 2 y) d y

θ^{^{''}} = 3 θ

\int (2 u + 1)^{2} d u

What is the derivative of y=sqrt(3x) ?
The derivative of y=sqrt(3x) is (sqrt(3))/(2sqrt(x))
What is the first derivative of y=sqrt(3x) ?
The first derivative of y=sqrt(3x) is (sqrt(3))/(2sqrt(x))