What is the first derivative of 2xy ?

The first derivative of 2xy is 2y

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derivative of 2xy

derivative of

2 x y

2 y

Solution steps

\frac{d}{d x} (2 x y)

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 y \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= 2 y \cdot 1

Simplify

= 2 y

y^{^{'}} = y + sin (x) - cos (x)

f (x) = \frac{7 x - 5}{x ^{2} + 4 x}

f (x) = x^{4} + 4 x^{3} - 48 x^{2} + 6

\int_{0}^{9} 2 x d x

\int_{0}^{\frac{π}{3}} sec^{2} (x) d x