What is the derivative of x^2-5x+4 ?

The derivative of x^2-5x+4 is 2x-5

What is the first derivative of x^2-5x+4 ?

The first derivative of x^2-5x+4 is 2x-5

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\frac{d}{d x} (x^{2} - 5 x + 4)

2 x - 5

Solution steps

\frac{d}{d x} (x^{2} - 5 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (5 x) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (4) = 0

= 2 x - 5 + 0

Simplify

= 2 x - 5

\frac{d y}{d x} = y^{2} - 9, y (5) = 3

\frac{\partial}{\partial x} (u)

y^{^{''}} - 2 y^{^{'}} + 26 y = 0

\int x^{8} 4 x^{3} + 4 d x

\frac{\partial}{\partial x} (3 x^{2} y^{4} + 2)

What is the derivative of x^2-5x+4 ?
The derivative of x^2-5x+4 is 2x-5
What is the first derivative of x^2-5x+4 ?
The first derivative of x^2-5x+4 is 2x-5