What is the derivative of 9(5x^4ln(7x)+x^4) ?

The derivative of 9(5x^4ln(7x)+x^4) is 9(20x^3ln(7x)+9x^3)

What is the first derivative of 9(5x^4ln(7x)+x^4) ?

The first derivative of 9(5x^4ln(7x)+x^4) is 9(20x^3ln(7x)+9x^3)

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derivative of

9 (5 x^{4} ln (7 x) + x^{4})

9 (20 x^{3} ln (7 x) + 9 x^{3})

Solution steps

\frac{d}{d x} (9 (5 x^{4} ln (7 x) + x^{4}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (5 x^{4} ln (7 x) + x^{4})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 9 (\frac{d}{d x} (5 x^{4} ln (7 x)) + \frac{d}{d x} (x^{4}))

\frac{d}{d x} (5 x^{4} ln (7 x)) = 5 (4 x^{3} ln (7 x) + x^{3})

\frac{d}{d x} (x^{4}) = 4 x^{3}

= 9 (5 (4 x^{3} ln (7 x) + x^{3}) + 4 x^{3})

Expand

5 (4 x^{3} ln (7 x) + x^{3}) + 4 x^{3} : 20 x^{3} ln (7 x) + 9 x^{3}

= 9 (20 x^{3} ln (7 x) + 9 x^{3})

\int \frac{9 - x ^{2}}{x ^{4}} d x

\frac{d}{d x} (lo g_{2} (x^{3}))

100 - x^{2}

\int_{1}^{2} \frac{v ^{3} + 3 v ^{6}}{v ^{4}} d v

y = x^{2} - 2 x, y = 4 x + 7

What is the derivative of 9(5x^4ln(7x)+x^4) ?
The derivative of 9(5x^4ln(7x)+x^4) is 9(20x^3ln(7x)+9x^3)
What is the first derivative of 9(5x^4ln(7x)+x^4) ?
The first derivative of 9(5x^4ln(7x)+x^4) is 9(20x^3ln(7x)+9x^3)