What is the integral of sec^3(x) ?

The integral of sec^3(x) is 1/2 sec(x)tan(x)+1/2 ln|tan(x)+sec(x)|+C

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integral of sec^3(x)

\int sec^{3} (x) d x

\frac{1}{2} sec (x) tan (x) + \frac{1}{2} ln ∣ tan (x) + sec (x) ∣ + C

Solution steps

\int sec^{3} (x) d x

Apply Integral Reduction

= \frac{sec ^{2} ( x ) sin ( x )}{2} + \frac{1}{2} \cdot \int sec (x) d x

\int sec (x) d x = ln ∣ tan (x) + sec (x) ∣

= \frac{sec ^{2} ( x ) sin ( x )}{2} + \frac{1}{2} ln ∣ tan (x) + sec (x) ∣

Simplify

\frac{sec ^{2} ( x ) sin ( x )}{2} + \frac{1}{2} ln ∣ tan (x) + sec (x) ∣ : \frac{1}{2} sec (x) tan (x) + \frac{1}{2} ln ∣ tan (x) + sec (x) ∣

= \frac{1}{2} sec (x) tan (x) + \frac{1}{2} ln ∣ tan (x) + sec (x) ∣

Add a constant to the solution

= \frac{1}{2} sec (x) tan (x) + \frac{1}{2} ln ∣ tan (x) + sec (x) ∣ + C

\frac{\partial}{\partial y} (\frac{x + y}{z - 2 y})

x \to 0 lim ((1 + 2 (\frac{1}{y}))^{\frac{1}{x}})

\int_{2}^{3} \frac{19}{3 - x} d x

y^{^{'}} = 5 x e^{y}

\frac{d}{d x} (x ln (x y))

What is the integral of sec^3(x) ?
The integral of sec^3(x) is 1/2 sec(x)tan(x)+1/2 ln|tan(x)+sec(x)|+C