What is the solution for (dy)/(dt)=e^{4t+5y} ?

The solution for (dy)/(dt)=e^{4t+5y} is y=-(ln(-5/4 e^{4t}-c_{1}))/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dt)=e^{4t+5y}

\frac{d y}{d t} = e^{4 t + 5 y}

y = - \frac{ln ( - \frac{5}{4} e ^{4 t} - c _{1} )}{5}

Solution steps

\frac{d y}{d t} = e^{4 t + 5 y}

Solve separable ODE:

y = - \frac{ln ( - \frac{5}{4} e ^{4 t} - c _{1} )}{5}

y = - \frac{ln ( - \frac{5}{4} e ^{4 t} - c _{1} )}{5}

y = ln (π)

\frac{d}{d x} (\frac{4 x ^{2} + 4 x + 8}{x})

\int x (ln (x))^{2} d x

cos^{3} (tan (3 x))

\int 2 e^{t} d t

What is the solution for (dy)/(dt)=e^{4t+5y} ?
The solution for (dy)/(dt)=e^{4t+5y} is y=-(ln(-5/4 e^{4t}-c_{1}))/5