What is the first derivative of 4x-3 ?

The first derivative of 4x-3 is 4

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derivative of 4x-3

derivative of

4 x - 3

4

Solution steps

\frac{d}{d x} (4 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x) - \frac{d}{d x} (3)

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (3) = 0

= 4 - 0

Simplify

= 4

y = \frac{4 x}{1 + x ^{2}}, (4, \frac{16}{17})

\int_{0}^{\frac{π}{2}} - 3 sin^{2} (3 x) d x

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