What is the derivative of 16-5x^2 ?

The derivative of 16-5x^2 is -10x

What is the first derivative of 16-5x^2 ?

The first derivative of 16-5x^2 is -10x

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\frac{d}{d x} (16 - 5 x^{2})

- 10 x

Solution steps

\frac{d}{d x} (16 - 5 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (16) - \frac{d}{d x} (5 x^{2})

\frac{d}{d x} (16) = 0

\frac{d}{d x} (5 x^{2}) = 10 x

= 0 - 10 x

Simplify

= - 10 x

x \to 2 - lim (sin (\frac{1}{x - 2}))

x \to 2 lim (x^{2} + 2)

\frac{d y}{d x} = 18 - y

(1 + x) e^{2 x}

\int_{0}^{5} 1 + 3 x d x

What is the derivative of 16-5x^2 ?
The derivative of 16-5x^2 is -10x
What is the first derivative of 16-5x^2 ?
The first derivative of 16-5x^2 is -10x