What is the slope ofintercept 6x^2+xy+3y^2=40 ?

The slope ofintercept 6x^2+xy+3y^2=40 is (-12x-y)/(x+6y)

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slope ofintercept 6x^2+xy+3y^2=40

slope intercept

6 x^{2} + x y + 3 y^{2} = 40

\frac{- 12 x - y}{x + 6 y}

Solution steps

6 x^{2} + x y + 3 y^{2} = 40

Use implicit differentiation to find the slope of

6 x^{2} + x y + 3 y^{2} = 40

Implicit Derivative

\frac{d y}{d x}

6 x^{2} + x y + 3 y^{2} = 40 : \frac{- 12 x - y}{x + 6 y}

\frac{- 12 x - y}{x + 6 y}

\int t arcsin (t) d t

2 x^{3} x + 1

\frac{e ^{- 2 s}}{s + 1}

\frac{d}{d x} ((\frac{3 x ^{2}}{2 x + 4})^{3})

\int e^{l n ∣ t ∣} d t

What is the slope ofintercept 6x^2+xy+3y^2=40 ?
The slope ofintercept 6x^2+xy+3y^2=40 is (-12x-y)/(x+6y)