What is the derivative of y=sqrt(x) ?

The derivative of y=sqrt(x) is 1/(2sqrt(x))

What is the first derivative of y=sqrt(x) ?

The first derivative of y=sqrt(x) is 1/(2sqrt(x))

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derivative of

y = x

\frac{1}{2 x}

Solution steps

\frac{d}{d x} (x)

Apply radical rule:

a = a^{\frac{1}{2}}

= \frac{d}{d x} (x^{\frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{2} x^{\frac{1}{2} - 1}

Simplify

\frac{1}{2} x^{\frac{1}{2} - 1} : \frac{1}{2 x}

= \frac{1}{2 x}

\frac{( s ^{2} + 5 )}{( s ^{2} + 5 s + 16 )}

\int (40 - \frac{2}{sec ( x )}) d x

\int \frac{z ^{2}}{p ^{2} + z ^{2}} d z

\int 5 x^{2} + 4 d x

x \to 9 lim (7 x - 4)

What is the derivative of y=sqrt(x) ?
The derivative of y=sqrt(x) is 1/(2sqrt(x))
What is the first derivative of y=sqrt(x) ?
The first derivative of y=sqrt(x) is 1/(2sqrt(x))