What is the integral from-2 to 2 of sqrt(x+2) ?

The integral from-2 to 2 of sqrt(x+2) is 16/3

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integral from-2 to 2 of sqrt(x+2)

\int_{- 2}^{2} x + 2 d x

\frac{16}{3}

Decimal

5.33333 \dots

Solution steps

\int_{- 2}^{2} x + 2 d x

Apply u-substitution

: \int_{0}^{4} u d u

= \int_{0}^{4} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{4}

= [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{4}

Compute the boundaries:

\frac{16}{3}

= \frac{16}{3}

f (x) = (\frac{x - 4}{x + 4})^{4}

\int_{0}^{1} \frac{1}{1 + sin ( 2 x )} d x

\int \frac{( x + 6 )}{( x + 7 )} d x

\frac{d}{d y} (2 x - y)

\frac{d}{d x} (\frac{ln ( x ^{2} )}{x ^{2}})

What is the integral from-2 to 2 of sqrt(x+2) ?
The integral from-2 to 2 of sqrt(x+2) is 16/3