What is the tangent of y= 1/(3x+4),(1, 1/7) ?

The tangent of y= 1/(3x+4),(1, 1/7) is y=-3/49 x+10/49

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tangent of y= 1/(3x+4),(1, 1/7)

tangent of

y = \frac{1}{3 x + 4}, (1, \frac{1}{7})

y = - \frac{3}{49} x + \frac{10}{49}

Solution steps

Find the slope of

y = \frac{1}{3 x + 4} : \frac{d y}{d x} = - \frac{3}{( 3 x + 4 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{3}{49}

Find the line with slope m=

- \frac{3}{49}

and passing through

(1, \frac{1}{7}) : y = - \frac{3}{49} x + \frac{10}{49}

y = - \frac{3}{49} x + \frac{10}{49}

\int \frac{x ^{3}}{x ^{2} + 25} d x

\int \frac{1}{x ^{2} - 1} d x

\frac{\partial}{\partial x} (3 x^{2} y + 4 x y^{2})

x \frac{d y}{d x} - 2 y = 2

\frac{\partial}{\partial y} (x ln (x^{2} + y^{2}))

What is the tangent of y= 1/(3x+4),(1, 1/7) ?
The tangent of y= 1/(3x+4),(1, 1/7) is y=-3/49 x+10/49