What is laplacetransform g(t)=sin(2t+5) ?

The answer to laplacetransform g(t)=sin(2t+5) is (sin(5)s+2cos(5))/(s^2+4)

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laplacetransform g(t)=sin(2t+5)

laplace transform

g (t) = sin (2 t + 5)

\frac{sin ( 5 ) s + 2 cos ( 5 )}{s ^{2} + 4}

Solution steps

L {sin (2 t + 5)}

Use Laplace Transform table:

L {sin (a t + b)} = \frac{s \cdot sin ( b ) + a \cdot cos ( b )}{s ^{2} + a ^{2}}

L {sin (2 t + 5)} = \frac{s sin ( 5 ) + 2 cos ( 5 )}{s ^{2} + 2 ^{2}}

= \frac{s sin ( 5 ) + 2 cos ( 5 )}{s ^{2} + 2 ^{2}}

= \frac{sin ( 5 ) s + 2 cos ( 5 )}{s ^{2} + 4}

\int \frac{x ^{2}}{( 25 - x ^{2} ) ^{\frac{3}{2}}} d x

2 t + 1

x = 6 y^{3}, x = 21 y^{2}

\frac{d y}{d t} = \frac{4 y}{t}

\int 3 t^{- 7} d t

What is laplacetransform g(t)=sin(2t+5) ?
The answer to laplacetransform g(t)=sin(2t+5) is (sin(5)s+2cos(5))/(s^2+4)