What is the derivative of y=sqrt(-2x^2+24) ?

The derivative of y=sqrt(-2x^2+24) is -(2x)/(sqrt(-2x^2+24))

What is the first derivative of y=sqrt(-2x^2+24) ?

The first derivative of y=sqrt(-2x^2+24) is -(2x)/(sqrt(-2x^2+24))

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derivative of

y = - 2 x^{2} + 24

- \frac{2 x}{- 2 x ^{2} + 24}

Solution steps

\frac{d}{d x} (- 2 x^{2} + 24)

Apply the chain rule:

\frac{1}{2 - 2 x ^{2} + 24} \frac{d}{d x} (- 2 x^{2} + 24)

= \frac{1}{2 - 2 x ^{2} + 24} \frac{d}{d x} (- 2 x^{2} + 24)

\frac{d}{d x} (- 2 x^{2} + 24) = - 4 x

= \frac{1}{2 - 2 x ^{2} + 24} (- 4 x)

Simplify

\frac{1}{2 - 2 x ^{2} + 24} (- 4 x) : - \frac{2 x}{- 2 x ^{2} + 24}

= - \frac{2 x}{- 2 x ^{2} + 24}

2 x^{3} - x^{2} - 5 x, - x^{2} + 3 x, - 2, 0

\int_{0}^{1} e^{x} (e^{x} - 1) d x

\int e^{x} (- x) d x

\int \frac{1}{u ln ( u ) - u} d u

30 t^{2}

What is the derivative of y=sqrt(-2x^2+24) ?
The derivative of y=sqrt(-2x^2+24) is -(2x)/(sqrt(-2x^2+24))
What is the first derivative of y=sqrt(-2x^2+24) ?
The first derivative of y=sqrt(-2x^2+24) is -(2x)/(sqrt(-2x^2+24))