What is the integral from 0 to 1 of x/(25+144x^4) ?

The integral from 0 to 1 of x/(25+144x^4) is 1/120 arctan(12/5)

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integral from 0 to 1 of x/(25+144x^4)

\int_{0}^{1} \frac{x}{25 + 144 x ^{4}} d x

\frac{1}{120} arctan (\frac{12}{5})

Decimal

0.00980 \dots

Solution steps

\int_{0}^{1} \frac{x}{25 + 144 x ^{4}} d x

Compute the indefinite integral:

\int \frac{x}{25 + 144 x ^{4}} d x = \frac{1}{120} arctan (\frac{12}{5} x^{2}) + C

Compute the boundaries:

\int_{0}^{1} \frac{x}{25 + 144 x ^{4}} d x = \frac{1}{120} arctan (\frac{12}{5}) - 0

= \frac{1}{120} arctan (\frac{12}{5}) - 0

Simplify

= \frac{1}{120} arctan (\frac{12}{5})

\frac{d}{d x} (cos (3 x - 1))

\int_{0}^{1} (e^{x} - 1) d x

y^{^{''}} + 4 y = 0, y (0) = 5, y^{^{'}} (0) = 1

\int_{0}^{s} \frac{1}{0.2 s + 10} d s

\frac{\partial}{\partial x} (\frac{1}{x + 2})

What is the integral from 0 to 1 of x/(25+144x^4) ?
The integral from 0 to 1 of x/(25+144x^4) is 1/120 arctan(12/5)