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Popular >

y^'=x^2-2

Solution

y^{^{'}} = x^{2} - 2

Solution

y = \frac{x ^{3}}{3} - 2 x + c_{1}

Solution steps

y^{'} (x) = x^{2} - 2

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int x^{2} - 2 d x

\int x^{2} - 2 d x = \frac{x ^{3}}{3} - 2 x + c_{1}

y = \frac{x ^{3}}{3} - 2 x + c_{1}

Graph

Popular Examples

tangent of 1/(x+4),\at x=5 tangent of

\frac{1}{x + 4}, at x = 5

derivative of ln(x^3+2x^2+2x)derivative of

ln (x^{3} + 2 x^{2} + 2 x)

integral of (4sqrt(x))/(x-1)

\int \frac{4 x}{x - 1} d x

y^{''}-y=0,y(0)=1,y^'(0)=0

y^{^{''}} - y = 0, y (0) = 1, y^{^{'}} (0) = 0

y^{^{'}} = 5 t y^{2}

Frequently Asked Questions (FAQ)

What is the solution for y^'=x^2-2 ?
The solution for y^'=x^2-2 is y=(x^3)/3-2x+c_{1}