What is the derivative of \sqrt[3]{1+x} ?

The derivative of \sqrt[3]{1+x} is 1/(3(1+x)^{2/3)}

What is the first derivative of \sqrt[3]{1+x} ?

The first derivative of \sqrt[3]{1+x} is 1/(3(1+x)^{2/3)}

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derivative of

3 1 + x

\frac{1}{3 ( 1 + x ) ^{\frac{2}{3}}}

Solution steps

\frac{d}{d x} (3 1 + x)

Apply the chain rule:

\frac{1}{3 ( 1 + x ) ^{\frac{2}{3}}} \frac{d}{d x} (1 + x)

= \frac{1}{3 ( 1 + x ) ^{\frac{2}{3}}} \frac{d}{d x} (1 + x)

\frac{d}{d x} (1 + x) = 1

= \frac{1}{3 ( 1 + x ) ^{\frac{2}{3}}} \cdot 1

Simplify

= \frac{1}{3 ( 1 + x ) ^{\frac{2}{3}}}

(x - 1)^{\frac{1}{2}}

x + y

\int \frac{x}{3 x - 2} d x

x \to \frac{3 π}{2} lim (cos (x))

\int \frac{1}{9 - ( 3 x + 5 ) ^{2}} d x

What is the derivative of \sqrt[3]{1+x} ?
The derivative of \sqrt[3]{1+x} is 1/(3(1+x)^{2/3)}
What is the first derivative of \sqrt[3]{1+x} ?
The first derivative of \sqrt[3]{1+x} is 1/(3(1+x)^{2/3)}