What is the derivative of f(x)=2x^2-x-3 ?

The derivative of f(x)=2x^2-x-3 is 4x-1

What is the first derivative of f(x)=2x^2-x-3 ?

The first derivative of f(x)=2x^2-x-3 is 4x-1

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derivative of

f (x) = 2 x^{2} - x - 3

4 x - 1

Solution steps

\frac{d}{d x} (2 x^{2} - x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d x}{d x} - \frac{d}{d x} (3)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d x}{d x} = 1

\frac{d}{d x} (3) = 0

= 4 x - 1 - 0

Simplify

= 4 x - 1

\int 3 t^{- 1} d t

\frac{d}{d x} (arccos (\frac{x}{5}))

\frac{x}{x ^{2} + 13 x + 40}

\int \frac{sec ^{2} ( \frac{1}{x ^{7}} )}{x ^{8}} d x

\int \frac{2 x ^{2} - x + 3}{x ( x ^{2} + 1 )} d x

What is the derivative of f(x)=2x^2-x-3 ?
The derivative of f(x)=2x^2-x-3 is 4x-1
What is the first derivative of f(x)=2x^2-x-3 ?
The first derivative of f(x)=2x^2-x-3 is 4x-1