What is the derivative of y=7x^{-3} ?

The derivative of y=7x^{-3} is -(21)/(x^4)

What is the first derivative of y=7x^{-3} ?

The first derivative of y=7x^{-3} is -(21)/(x^4)

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derivative of

y = 7 x^{- 3}

- \frac{21}{x ^{4}}

Solution steps

\frac{d}{d x} (7 x^{- 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 7 (- 3 x^{- 3 - 1})

Simplify

7 (- 3 x^{- 3 - 1}) : - \frac{21}{x ^{4}}

= - \frac{21}{x ^{4}}

\frac{d}{d y} (ln (3 x^{2} - y^{3} - 3))

\frac{3 x ^{2}}{1 - x - x ^{5}}

x \to 3 lim (ln (\frac{1}{3 - x}) - 3)

\int \frac{x ^{2} + 6 x - 5}{2 x ^{3} + 3 x ^{2} - 2 x} d x

\frac{s + 1}{s ^{2} + 25}

What is the derivative of y=7x^{-3} ?
The derivative of y=7x^{-3} is -(21)/(x^4)
What is the first derivative of y=7x^{-3} ?
The first derivative of y=7x^{-3} is -(21)/(x^4)