What is (\partial)/(\partial y)(x-1/(y^2)) ?

The answer to (\partial)/(\partial y)(x-1/(y^2)) is 2/(y^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(x-1/(y^2))

\frac{\partial}{\partial y} (x - \frac{1}{y ^{2}})

\frac{2}{y ^{3}}

Solution steps

\frac{\partial}{\partial y} (x - \frac{1}{y ^{2}})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x) - \frac{\partial}{\partial y} (\frac{1}{y ^{2}})

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (\frac{1}{y ^{2}}) = - \frac{2}{y ^{3}}

= 0 - (- \frac{2}{y ^{3}})

Simplify

= \frac{2}{y ^{3}}

y = - x^{2} + 4, y = - \frac{x ^{2}}{2} + 2

\frac{1}{( s ^{2} + s + 1 )}

x \to 5 lim (4 x - 3)

\int \frac{ln ( ln ( x ) )}{x ln ( x )} d x

\frac{6}{4 x + 1}

What is (\partial)/(\partial y)(x-1/(y^2)) ?
The answer to (\partial)/(\partial y)(x-1/(y^2)) is 2/(y^3)