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Popular >

y^'=((x^3-2y))/x

Solution

y^{^{'}} = \frac{( x ^{3} - 2 y )}{x}

Solution

y = \frac{x ^{3}}{5} + \frac{c _{1}}{x ^{2}}

Solution steps

y^{'} (x) = \frac{( x ^{3} - 2 y )}{x}

Solve linear ODE:

y = \frac{x ^{3}}{5} + \frac{c _{1}}{x ^{2}}

y = \frac{x ^{3}}{5} + \frac{c _{1}}{x ^{2}}

Popular Examples

derivative of 6sin(2x-3cos(3x))

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derivative of-536870912sin(2x)

\frac{d}{d x} (- 536870912 sin (2 x))

derivative of f(x)=sqrt(10+x)derivative of

f (x) = 10 + x

tangent of f(x)=9+5x^2-2x^3,(1,12)tangent of

f (x) = 9 + 5 x^{2} - 2 x^{3}, (1, 12)

tangent of f(x)=x^3-3x^2+2x-2 tangent of

f (x) = x^{3} - 3 x^{2} + 2 x - 2

Frequently Asked Questions (FAQ)

What is the solution for y^'=((x^3-2y))/x ?
The solution for y^'=((x^3-2y))/x is y=(x^3)/5+(c_{1})/(x^2)