What is the derivative of (7x)/(8-tan(x)) ?

The derivative of (7x)/(8-tan(x)) is (7(8-tan(x)+xsec^2(x)))/((8-tan(x))^2)

What is the first derivative of (7x)/(8-tan(x)) ?

The first derivative of (7x)/(8-tan(x)) is (7(8-tan(x)+xsec^2(x)))/((8-tan(x))^2)

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derivative of

\frac{7 x}{8 - tan ( x )}

\frac{7 ( 8 - tan ( x ) + x sec ^{2} ( x ) )}{( 8 - tan ( x ) ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{7 x}{8 - tan ( x )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (\frac{x}{8 - tan ( x )})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 7 \cdot \frac{\frac{d x}{d x} ( 8 - tan ( x ) ) - \frac{d}{d x} ( 8 - tan ( x ) ) x}{( 8 - tan ( x ) ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (8 - tan (x)) = - sec^{2} (x)

= 7 \cdot \frac{1 \cdot ( 8 - tan ( x ) ) - ( - sec ^{2} ( x ) ) x}{( 8 - tan ( x ) ) ^{2}}

Simplify

7 \cdot \frac{1 \cdot ( 8 - tan ( x ) ) - ( - sec ^{2} ( x ) ) x}{( 8 - tan ( x ) ) ^{2}} : \frac{7 ( 8 - tan ( x ) + x sec ^{2} ( x ) )}{( 8 - tan ( x ) ) ^{2}}

= \frac{7 ( 8 - tan ( x ) + x sec ^{2} ( x ) )}{( 8 - tan ( x ) ) ^{2}}

\int \frac{4 x ^{2} + x + 4}{( x ^{2} + 1 ) ^{2}} d x

\int_{a}^{b} (\frac{1}{x ^{3}} + 3 x) d x

\int - \frac{1}{1 + sin ( x )} d x

x y^{^{'}} - 2 y = x^{4} - 4

\frac{( 3 y ^{2} - t ^{2} )}{( y ^{5} )} \cdot y^{^{'}} + \frac{t}{( 2 y ^{4} )} = 0, y (1) = 3

What is the derivative of (7x)/(8-tan(x)) ?
The derivative of (7x)/(8-tan(x)) is (7(8-tan(x)+xsec^2(x)))/((8-tan(x))^2)
What is the first derivative of (7x)/(8-tan(x)) ?
The first derivative of (7x)/(8-tan(x)) is (7(8-tan(x)+xsec^2(x)))/((8-tan(x))^2)